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NCARB ARE 5.0 Project Development and Documentation Exam Sample Questions (Q26-Q31):
NEW QUESTION # 26
Where is the proper place to put a vapor barrier in a cold climate?
- A. On the interior between the gypsum wallboard and the framing
- B. On the exterior between the metal siding and the sheathing
- C. On the exterior between the framing and the sheathing
- D. In the cavity of the framing space
Answer: A
Explanation:
In cold climates, the vapor drive is from the warm interior to the cold exterior during winter. The vapor retarder/barrier belongs on the warm-in-winter side of the assembly-i.e., behind the interior gypsum, before the framing/insulation-to prevent interior moisture from reaching cold layers where it could condense.
PDD references: Psychrometrics & vapor drive; vapor retarder placement (ASHRAE; IBC/IECC guidance; ARE 5.0 PDD-Thermal & Moisture Protection).
NEW QUESTION # 27 
Refer to the exhibit.
It is required to cut a hole in the web of the beam shown.
Which of the locations would be best? Check the two that apply.
- A. Location 3
- B. Location 4
- C. Location 5
- D. Location 1
- E. Location 2
Answer: B,E
Explanation:
Cutting holes in beam webs is common for running mechanical, electrical, or plumbing services but must be done carefully to avoid weakening structural integrity.
Holes should be located near mid-span supports (points of low bending moment and high shear) to reduce impact on beam bending strength.
Holes should not be located near areas of maximum bending moment (typically mid-span between supports), because this is where the beam experiences maximum tension or compression.
Locations 2 and 4 are at or near the beam supports (shear zones), and generally small holes can be cut there, following size limits and reinforcement guidelines.
Locations 1, 3, and 5 are closer to mid-span or areas of high bending stress, so holes here risk compromising the beam's moment capacity.
References:
NCARB ARE 5.0 Review Manual, Structural Systems chapter
Steel construction and beam design guidelines (AISC)
Building codes and structural engineering best practices for web penetrations
NEW QUESTION # 28
Temporary shoring of a masonry wall should remain in place until what point?
- A. Foundations are backfilled
- B. Mortar joints are struck
- C. Lateral bracing connections are complete
- D. Horizontal reinforcing is installed
Answer: C
Explanation:
(PDD) Study Guide References:
Temporary shoring in masonry construction supports walls until they gain sufficient stability. It should remain in place until:
The wall is laterally braced or tied back to a stable structure to resist wind and other lateral loads.
Mortar may have hardened but shoring removal depends on the overall stability.
Horizontal reinforcing and backfilling provide some support but do not replace lateral bracing.
Thus, temporary shoring should remain until all lateral bracing connections are complete, ensuring the wall's stability.
Reference:
NCARB ARE 5.0 Review Manual, Construction Methods chapter
Masonry construction standards and OSHA guidelines on temporary shoring
NEW QUESTION # 29
In addition to reducing heat conductance, the thermal break in the construction of metal window frames does which of the following?
- A. Reduces condensation
- B. Reduces the cost of manufacture
- C. Increases air infiltration
- D. Increases sound transmission
Answer: A
Explanation:
A thermal break in metal window frames interrupts the conductive path of heat through the frame, reducing heat transfer.
This reduces the chance that the interior surface of the frame will drop below the dew point temperature, thereby reducing condensation (surface moisture buildup).
Thermal breaks do not increase air infiltration; they help maintain thermal performance.
They reduce sound transmission, so B is incorrect.
Thermal breaks typically increase cost and complexity, so D is incorrect.
Reference:
NCARB ARE 5.0 Review Manual, Building Enclosure and Materials chapters
Fenestration performance and condensation control guides
NEW QUESTION # 30
An architect needs to reduce the budget by $150,000 for a proposed civic auditorium. Currently the project requires the following flooring materials:
* Stained concrete: 100,000 square feet
* Carpet: 50,000 square feet
* Ceramic tile: 20,000 square feet
* Vinyl composite tile (VCT): 25,000 square feet
The flooring material costs are as follows:
* Stained concrete: $6.00/sq ft
* Sealed concrete: $2.00/sq ft
* Carpet: $8.75/sq ft
* Ceramic tile: $15.00/sq ft
* VCT: $5.75/sq ft
* Vinyl plank flooring: $7.00/sq ft
Which of the following combinations of changes results in these savings?
- A. Change 15,000 sq ft of VCT to vinyl plank flooring and substitute 10,000 sq ft of VCT for carpet.
- B. Change 20,000 sq ft of stained concrete to VCT and substitute 30,000 sq ft of vinyl plank flooring for carpet.
- C. Change 20,000 sq ft of stained concrete to VCT and substitute 10,000 sq ft of VCT for ceramic tile.
- D. Change 25,000 sq ft of stained concrete to sealed concrete and substitute 30,000 sq ft of vinyl plank flooring for carpet.
Answer: C
Explanation:
Verified answer: C. Change 20,000 sq ft of stained concrete to VCT and substitute 10,000 sq ft of VCT for ceramic tile.
Comprehensive Detailed Explanation with all NCARB ARE 5.0 Project Development and Documentation (PDD) Study Guide References:
Calculate savings for each option by comparing current costs to proposed changes.
Verified answer: C. Change 20,000 sq ft of stained concrete to VCT and substitute 10,000 sq ft of VCT for ceramic tile.
Comprehensive Detailed Explanation with all NCARB ARE 5.0 Project Development and Documentation (PDD) Study Guide References:
Calculate savings for each option by comparing current costs to proposed changes.

Check if this matches required savings:
No, it's less than $150,000. So let's check others briefly.
Total savings = $100,000 + $52,500 = $152,500 # Meets and exceeds required savings
Options A and B will be less, so the answer should be D.
Summary:
Option D results in approximately $152,500 savings, meeting the $150,000 target.
Reference:
NCARB ARE 5.0 Review Manual, Project Cost Control and Materials chapter Construction cost estimating principles and value engineering strategies Change 20,000 sf stained concrete ($6.00/sf) to VCT ($5.75/sf) Savings per sf = $6.00 - $5.75 = $0.25 Total savings = 20,000 sf × $0.25 = $5,000 Substitute 10,000 sf of VCT ($5.75/sf) for ceramic tile ($15.00/sf) Savings per sf = $15.00 - $5.75 = $9.25 Total savings = 10,000 sf × $9.25 = $92,500 Total savings = $5,000 + $92,500 = $97,500 Check if this matches required savings:
No, it's less than $150,000. So let's check others briefly.
Option D:
Change 25,000 sf stained concrete ($6.00/sf) to sealed concrete ($2.00/sf) Savings per sf = $6.00 - $2.00 = $4.00 Total = 25,000 × 4.00 = $100,000 Substitute 30,000 sf vinyl plank ($7.00/sf) for carpet ($8.75/sf) Savings per sf = $8.75 - $7.00 = $1.75 Total = 30,000 × 1.75 = $52,500 Total savings = $100,000 + $52,500 = $152,500 # Meets and exceeds required savings Options A and B will be less, so the answer should be D.
Summary:
Option D results in approximately $152,500 savings, meeting the $150,000 target.
Reference:
NCARB ARE 5.0 Review Manual, Project Cost Control and Materials chapter Construction cost estimating principles and value engineering strategies
NEW QUESTION # 31
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